Residual r = θ′ + θ of the network: zero where the law holds
- Train with the start value in the loss.
- Now choose none: which curve does it find, and why?
- Use only 4 collocation points: where does the residual stay large?
The start value θ(0) = 1
Points where the law is checked; nothing is measured there.
Largest error
θ(0) of the network
Loss over the training steps (log scale)
- Train with the law: which cooling constant does it learn?
- Switch the law off and train: what happens after 8 min?
- Show the true cooling: does 16 min match?
Cooling constant k
At 16 min
Learned k [1/min] over the training steps
Energy E = x′²/2 + x²/2 of the network.
- Train over 2 periods, then over 10 periods.
- Press Equation only: why does the mass stay at rest?
- Find the damping: which value do the readings give?
More options
These options change all three steps.
Table: the readings
| Time [min] | Reading [°C] | True law [°C] |
|---|
| Time τ | Reading x | Exact x (ζ = 0.1) |
|---|
How it is computed
The readings are made in this page: the steel part from the true law T = 20 + 180 e−0.25 t °C plus fixed deviations of up to 2.5 °C, as in Lectures 4 and 5; the swinging mass from the exact motion for ζ = 0.1 plus noise.